o Meiosis II proceeds with prophase II, metaphase II, anaphase II, and telophase II.
o The final products are haploid gametes each with 23 chromosomes.
o In the case of the spermatocytes, four sperm cells are formed. In the case of the oocyte, a single ovum is formed.
o In the female, telophase II produces one gamete and a second polar body.
o If during anaphase I or II the centromere of any chromosome doesn’t split, this is called nondisjunction (it can also happen in mitosis but the ramifications are less severe).
o As a result of primary nondisjunction (nondisjunction in anaphase I), one of the cells with end up with two extra chromatids
o Complete extra chromosome) and the other will be missing a chromosome.
o If nondisjuction occurs in anaphase II that will result in one cell having an extra chromatid and one lacking a chromatid.
o The number of different possible gametes that can be formed by diploid organisms as a result of independent assortment of chromosomes during meiosis can be calculated by using the formula 2^n where n is the number of heterozygous genes.
o Ex. AaBbCc ⇒ this can produce 2^3 number of different haploid cells.
o Parthenogenesis (means the growth and development of an embryo or seed without fertilization by a male.
o Parthenogenesis occurs naturally in some lower plants, invertebrates (e.g. water fleas, aphids) and some vertebrates (e.g. lizards, salamanders, some fish, and even turkeys).
o Parthenogenetic populations are typically all-female.
o As with all types of asexual reproduction, there are both costs and benefits associated with parthenogenesis.
o Spermatogonium (diploid) ⇒ primary spermatocyte (diploid) ⇒ 2ndary spermatocyte (haploid) ⇒ spermatid (haploid) ⇒ spermatozoa (haploid)
o Oogonium (diploid) ⇒ primary oocyte (diploid) ⇒ secondary oocyte (haploid) ⇒ zygote (diploid)
o A Barr body is a permanently inactivated X chromosome that forms a dense stainable nuclear mass.
o A normal female with XX inactivates one of her X’s while expressing the other.
o She therefore has 1 Barr body.
o A normal male, who is XY, does not inactivate his only X chromosome, and therefore has no Barr bodies.
o The rule is that the number of X chromosomes is always 1 MORE than the number of Barr bodies.
o Ex. A person with 2 Barr bodies has to have 3 X chromosomes.